Unit 3: Pair of Straight Lines

Table of Contents

Homogeneous Equation of 2nd Degree

Definition and Representation

A homogeneous equation of the second degree is an equation where every term has a total degree of 2.

ax² + 2hxy + by² = 0

This equation always represents a pair of straight lines passing through the origin (0, 0).

We can see this by dividing by (assuming x ≠ 0):
a + 2h(y/x) + b(y/x)² = 0
This is a quadratic equation in (y/x). Let m = y/x (the slope).
bm² + 2hm + a = 0
If the roots of this are m₁ and m₂, then:
m₁ + m₂ = -2h/b
m₁m₂ = a/b
The two lines are y/x = m₁ and y/x = m₂, or y = m₁x and y = m₂x.

Angle Between Lines

If θ is the angle between the two lines y = m₁x and y = m₂x, we know from Unit 2 that tan(θ) = |(m₁ - m₂) / (1 + m₁m₂)|.

We can write (m₁ - m₂)² = (m₁ + m₂)² - 4m₁m₂
(m₁ - m₂)² = (-2h/b)² - 4(a/b) = (4h² - 4ab) / b²
|m₁ - m₂| = sqrt(4h² - 4ab) / |b| = 2*sqrt(h² - ab) / |b|
And 1 + m₁m₂ = 1 + a/b = (a + b) / b
Substituting these in:

tan(θ) = | 2 * sqrt(h² - ab) / (a + b) |

This formula gives the angle between the lines represented by ax² + 2hxy + by² = 0.

Condition for Parallel/Coincident Lines

The lines are parallel or coincident if the angle θ = 0, which means tan(θ) = 0. This happens when the numerator is zero.

Condition: h² - ab = 0 or h² = ab

This means the quadratic for m has equal roots, so m₁ = m₂.

Condition for Perpendicular Lines

The lines are perpendicular if the angle θ = 90°, which means tan(θ) is undefined. This happens when the denominator is zero.

Condition: a + b = 0
(i.e., Coefficient of x² + Coefficient of y² = 0)

This corresponds to m₁m₂ = a/b = -b/b = -1.

Bisector of Angles Between Pair of Straight Lines

The combined equation of the two lines (which are also perpendicular to each other) that bisect the angles between ax² + 2hxy + by² = 0 is given by a standard formula:

Equation of Angle Bisectors: (x² - y²) / (a - b) = xy / h
Derivation (Sketch):
  1. Let the two lines be y - m₁x = 0 and y - m₂x = 0.
  2. The locus of a point (x, y) on an angle bisector is where the perpendicular distance to both lines is equal.
  3. | (y - m₁x) / sqrt(1 + m₁²) | = | (y - m₂x) / sqrt(1 + m₂²) |
  4. This gives two equations (one for each bisector):
    (y - m₁x) / sqrt(1 + m₁²) = + (y - m₂x) / sqrt(1 + m₂²)
    (y - m₁x) / sqrt(1 + m₁²) = - (y - m₂x) / sqrt(1 + m₂²)
  5. Multiplying these two equations together and simplifying using the relations m₁ + m₂ = -2h/b and m₁m₂ = a/b eventually leads to the formula (x² - y²) / (a - b) = xy / h.

General Equation of 2nd Degree

The General Equation

The most general form of a second-degree equation is:

ax² + 2hxy + by² + 2gx + 2fy + c = 0

This equation can represent a circle, a parabola, an ellipse, a hyperbola, or, in a "degenerate" case, a pair of straight lines.

Condition to Represent a Pair of Straight Lines

This general equation represents a pair of straight lines if a specific condition is met. This condition is the most important part of this unit.

The condition can be expressed in two ways:

1. The "long" formula:

abc + 2fgh - af² - bg² - ch² = 0

2. The determinant form (Δ):

The determinant Δ (delta) must be zero.

Δ =
a h g
h b f
g f c
= 0
How to memorize the determinant: A common mnemonic is:
"A Hungry Girl
Had Big Fries
Go For Chocolate"

Note: If this condition is met, the angle θ between the two lines is still given by the same formula as the homogeneous case:
tan(θ) = | 2 * sqrt(h² - ab) / (a + b) |
This is because the first-degree terms (2gx + 2fy + c) only *translate* the lines away from the origin, they do not *rotate* them, so the angle between them remains the same.

Unit 3: Exam Quick Tips