Contact Hours: 60 | Full Marks: 100 (ESE=70/CCA=30)
A **Disjunctive Syllogism** (DS) is a valid deductive argument form whose major premise is a **disjunction** (an 'either-or' statement) and whose minor premise is the negation of one of the disjuncts, and whose conclusion is the affirmation of the other disjunct.
Example: "Either the lights are on or the circuit is broken. The lights are not on. Therefore, the circuit is broken."
Formula: (P ∨ Q), ¬P / ∴ Q
Important Note: The Strong Sense of "Or"
For the Disjunctive Syllogism to be valid, the 'or' in the major premise must be understood in the **inclusive sense** (P or Q or both) OR the **exclusive sense** (P or Q but not both). In modern logic, DS is valid even with the inclusive 'or'. However, arguments based on affirming a disjunct (e.g., P, ∴ ¬Q) are invalid (Fallacy of Affirming a Disjunct).
A **Hypothetical Syllogism** (HS) is a valid deductive argument form composed of at least one **hypothetical** (conditional or 'if-then') proposition, and often links three propositions together. The simplest form contains three conditional statements.
Links two conditional statements to infer a third conditional statement.
Example: "If it rains, the grass is wet. If the grass is wet, the sun will dry it. Therefore, if it rains, the sun will dry it."
Formula: (P → Q), (Q → R) / ∴ (P → R)
A **Dilemma** is a powerful and often rhetorically effective argument form that contains a **disjunctive premise** (the 'horns' of the dilemma) and two or more **conditional premises**. The dilemma presents a choice between two (or more) undesirable alternatives.
Dilemmas are classified based on the nature of their conclusion (simple or complex) and the nature of their minor premises (constructive or destructive).
| Type | Structure | Form |
|---|---|---|
| Simple Constructive | Two hypothetical premises, one disjunctive premise, and a simple (non-disjunctive) conclusion. | ((P → Q) ⋅ (R → Q)), (P ∨ R) / ∴ Q |
| Complex Constructive | Two hypothetical premises, one disjunctive premise, and a disjunctive conclusion. | ((P → Q) ⋅ (R → S)), (P ∨ R) / ∴ (Q ∨ S) |
| Simple Destructive | Two hypothetical premises, one disjunctive premise, and a simple (non-disjunctive) conclusion. | ((P → Q) ⋅ (P → R)), (¬Q ∨ ¬R) / ∴ ¬P |
| Complex Destructive | Two hypothetical premises, one disjunctive premise, and a disjunctive conclusion. | ((P → Q) ⋅ (R → S)), (¬Q ∨ ¬S) / ∴ (¬P ∨ ¬R) |
A dilemma is usually refuted not by proving it invalid, but by showing that its premises are false or unacceptable. There are three classic ways to rebut a dilemma:
Reject the disjunctive premise (P ∨ R) by proving that there is a third alternative (a 'third horn') that was not considered. Prove that both P and R are false.
Reject a conditional premise (P → Q) by showing that the consequent (Q) does not necessarily follow from the antecedent (P). Show a case where P is true but Q is false.
Construct a new dilemma whose conclusion is opposite to the original dilemma. This is a rhetorical device that proves the original argument form *may* be fallacious, but does not prove the original conclusion is false.
Exam Focus: Dilemma Testing
Be prepared to write out an example of a dilemma and then explicitly show how it can be rebutted using all three methods. Rebuttal by a Counter-Dilemma is often a Complex Destructive form with the consequents negated and switched.
Focus on the proper form of **DS** and **HS**, recognizing the two invalid forms related to conditionals (Affirming the Consequent, Denying the Antecedent). Spend most time learning the structure and the three ways to **Test (Refute) a Dilemma**.