FYUG Even Semester Exam, 2025

PHYSICS (4th Semester) | Course No.: PHYDSC-252
Subject: Electronics
Full Marks: 70 | Pass Marks: 28 | Duration: 3 Hours

UNIT-I

[2 × 2 = 4]

1. Short Answers (Any Two)

(a) Define conductivity and mobility.

Answer:

(b) Define static and dynamic resistance of a p-n junction.

Answer:

(c) Explain the principle of LED.

Answer: Light Emitting Diodes work on the principle of electroluminescence. When a p-n junction is forward biased, electrons cross from the n-side to the p-side and holes cross from the p-side to the n-side. During recombination, energy is released in the form of photons (light).

[5 + 5 = 10]

2. Long Answers (Option A & B)

(a) Explain in detail both forward and reverse bias characteristics of a p-n junction diode.

Answer: Forward Bias: When the P-region is connected to the positive terminal and N-region to the negative terminal. The depletion layer narrows, allowing current to flow exponentially after the knee voltage.
Reverse Bias: When the P-region is connected to the negative terminal and N-region to the positive terminal. The depletion layer widens, preventing majority carrier flow.

(b) Why is the current during reverse bias called reverse saturation current?

Answer: It is called "saturation" current because it reaches a constant maximum value very quickly and remains independent of the applied reverse voltage (until breakdown). It is caused by the flow of minority carriers.

UNIT-II

[2 + 4 = 6]

4. (a) Transistor in CE Mode

Explain input and output characteristics of a transistor in CE mode.

Answer: In Common Emitter (CE) mode, the emitter is common to both input (base) and output (collector).

[4]

4. (d) Numerical: Total Collector Current

In a CB configuration, I_E = 1 mA. If emitter is open, I_C = 60 μA. Find I_C if α = 0.9.

Answer: Given: I_E = 1 mA = 1000 μA, α = 0.9, I_CBO = 60 μA (current when emitter is open).
Formula: I_C = α I_E + I_CBO
I_C = (0.9 × 1000) + 60
I_C = 900 + 60 = 960 μA.

UNIT-III

[2 × 2 = 4]

5. Short Answers (Any Two)

(a) Why are h-parameters called hybrid parameters?

Answer: They are called "hybrid" because they use a mix of units. For example, h_ie is measured in Ohms (impedance), h_fe is dimensionless (current gain), and h_oe is in Siemens (admittance).

(b) Difference between virtual ground and real ground.

Answer: Real Ground: Physically connected to the earth/zero potential point.
Virtual Ground: A point in a circuit (like the inverting input of an OP-AMP) that is not physically grounded but is at zero potential because the other input is grounded and gain is infinite.

UNIT-IV

[5]

8. (c) Maxterms and Minterms

A B C Minterm (Symbol) Maxterm (Symbol)
0 0 0A'B'C' (m0)A+B+C (M0)
0 0 1A'B'C (m1)A+B+C' (M1)
1 1 1ABC (m7)A'+B'+C' (M7)

(Simplified table; full list includes all 8 combinations).

UNIT-V

[4 + 2 = 6]

10. (b) J-K Flip-Flop

Explain J-K Flip-flop and Race Around Condition.

Answer: The J-K Flip-flop is a universal flip-flop that eliminates the invalid state of an S-R flip-flop. Race Around Condition: Occurs in Level-triggered J-K flip-flops when J=1, K=1, and the clock pulse width is greater than the propagation delay of the gate. The output toggles multiple times during a single clock pulse, leading to an uncertain state.